TUGAS PERTEMUAN 2 JARINGAN KOMPUTER

 TUGAS JARINGAN KOMPUTER PERTEMUAN 2

Nama    : Tita Maharani Pusvita Sari

Kelas    : 12.4A.21

Nim      : 12190925

 Hitunglah jumlah Network dan Host yang akan terbentuk di alamat IP Address di bawah ini :

1. 192.168.10.1/30

2. 172.168.10.1/16

3. 172.168.10./22

4. 10.168.5.1/8

5. 10.168.5.1/17

 

Nomor 1:

Netmask = 255.255.255.252

In binary = 11111111. 11111111. 11111111.11111100

Used to calculate = 11111100

Network = 2^n

                  = 2^6

                  = 64 Network

Host = 2^h-2

          = 2^2-2

          = 2 Host

Nomor 2 :

Netmask = 255.255.0.0

In Binary = 11111111.11111111.00000000.00000000

Used to calculate = 00000000.00000000

Network = 2^n

                  = 2^0

                  = 1 Network

Host = 2^h-2

          = 2^16-2

          = 65534 Host

Nomor 3 :

Netmask = 255.255.252.0

In Binary = 11111111.11111111.11111100.00000000

Used to calculate = 11111100.00000000

Network = 2^n

                  = 2^6

                  = 64 Network

Host = 2^h-2

          = 2^10-2

          = 1022 Host

Nomor 4 :

Netmask = 255.0.0.0 

In Binary = 11111111.00000000.00000000.00000000

Used to calculate = 00000000.00000000.00000000

Network = 2^n

                  = 2^0

                  = 1 Network

Host = 2^h-2

          = 2^24-2

          = 167772614 Host

Nomor 5 :

Netmask = 255.255.128.0

In Binary = 11111111.11111111.10000000.00000000

Used to calculate = 11111111.10000000.00000000

Network = 2^n

                  = 2^9

                  = 512 Network

Host = 2^h-2

          = 2^15-2

          = 32766 Host